1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rotational Dynamics

  1. Nov 28, 2006 #1
    I have a quiz tommorrow and i am reviewing the harder problems and i cant get started on this one

    A bicycle Wheel is resting against a small step whose height is h=0.120 m. The weight and radius of the whell are W=25.0N and r=0.340 m. A horizontal force F is applied to the axle of the whell. As the magnitude of F increases, there comes a time when the wheel just begins to rise up and loses contact with the ground. What is the magnitude of the force when this happenes?

    I dont kinwo where to start i knwo the formulas
    and that the sum of the forces =0 but i dont know where to start

    Please help me get started

  2. jcsd
  3. Nov 28, 2006 #2


    User Avatar
    Science Advisor
    Homework Helper

    When the wheel starts to move, it will be rotating about the point of contact with the step. You will want to investigate torques and moment of inertia about that point.
  4. Nov 28, 2006 #3
    do u ahve to make the force perpendicular to the point f contact so one equation would be Frcos45=t

    then i dont knwo where to go i am trying to make stuff up to trigger my mind
  5. Nov 28, 2006 #4


    User Avatar
    Science Advisor
    Homework Helper

    What is the torque about the point of contact from the force acting at the point of contact? The only other forces are the applied horizontal force on the axle and gravity. The torques related to those forces will depend on the height of the step and the radius of the wheel. The torque for the horizontal force is easy to find in terms of F. The one for gravity is a bit tougher, but you can get it from the geometry of the problem.
  6. Nov 28, 2006 #5
    can u maybe help me with an equation i am confused on what u are saying
  7. Nov 28, 2006 #6


    User Avatar
    Science Advisor
    Homework Helper

    Draw a circle to represent the wheel and a horizontal tangent below the wheel to represent the ground. Draw the step of height h with the corner touching the wheel. Mg acts downward at the center of the wheel. F acts horizontally toward the step. The distance between the line of F and the contact point is r-h. The torque is F(r-h). Draw a radius from the center of the wheel straight down and another from the center to the point of contact. Call the angle between these radii θ. r-h can be written in terms of r and θ, so θ can be determined from r and h. The distance between the line of mg and the contact point can be written in terms of r and θ, and the torque from gravity is this distanve times mg. When F is big enough to make the F torque greater than the mg torque, the wheel will leave the ground.
  8. Nov 28, 2006 #7
    Say I am standing on the ground. As we know, gravity is acting on me. But why am I not sinking into the ground? Because there is an opposite force acting on me, this force is called the Normal force. If I want to lift off the ground, what do I have to do?
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Rotational Dynamics
  1. Rotational Dynamics (Replies: 26)

  2. Rotational dynamics (Replies: 4)

  3. Rotational Dynamics (Replies: 10)

  4. Rotational Dynamics (Replies: 3)