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**[SOLVED] rotational dynamics**

**1. Homework Statement**

A thin uniform rod has length 2.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest as angle theta=40 above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position.

**2. Homework Equations**

**3. The Attempt at a Solution**

I used mgh=.5mv^2 and found v=6.26

Since w=v/r I found the angular speed to be 6.26/2=3.1 rad/sec

I think this is how the problem is worked out...I'm just not sure. Thanks!