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1. The problem statement, all variables and given/known data

A thin uniform rod has length 2.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest as angle theta=40 above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position.

2. Relevant equations

3. The attempt at a solution

I used mgh=.5mv^2 and found v=6.26

Since w=v/r I found the angular speed to be 6.26/2=3.1 rad/sec

I think this is how the problem is worked out...I'm just not sure. Thanks!

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# Homework Help: Rotational dynamics

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