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Rotational energy

  1. Aug 15, 2009 #1
    Hi,

    I'm trying to understand the rotational energy of a fan impeller.

    I understand RE = 1/2Iw^2

    So therefore an impellor with an inertia of 50 kg m^2 spinning at 1440 rpm

    = 568405 J

    my question is does this figure need to be divided by 3600000 J to give Kw hours?
     
  2. jcsd
  3. Aug 15, 2009 #2
    Correct: 1KWH equals 3.6 x 106 joules
     
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