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My question is this:

A mail bag with a mass of 105 kg is suspended by a vertical rope of length 7.00 m. What horizontal force is necessary to hold the bag in a position displaced sideways a distance of 1.00 m from its initial position?

I tried to start this problem but I keep getting stuck. I start out figuring that it is an isosceles triganle with the legs being 7m and the base being 1 m. from there i figured that if i resolved the 1 meter into its horizontal and vertical components, I would be able to find the force using Newtons second law using 9.8 meters per second squared as the acceleration and the mass as 105 kg. but i think that using 9.8 meters per second squared is wrong because that is acceleration due to gravity and I only need horizontal acceleration....... I am confusing myself with this problem.......