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## Homework Statement

The uniform solid block in Fig. 10-37 has mass .172 kg and edge lengths a = 0.035 m, b = .084 m, and c = .014 m. Calculate its rotational inertia about an axis through one corner and perpendicular to the large faces.

http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c10/fig10_37.gif

## Homework Equations

I = Icom + M(h^2)

I = 1/12M(a^2+b^2)

## The Attempt at a Solution

With the pythagorean theorem, I found the distance it has shifted which was [1/2(a^2+b^2)]^1/2 = h so,

I = 1/12M(a^2+b^2) + M(h^2) substituting h with the previous discovery giving:

I = 1/12M(a^2+b^2) + M[1/2(a^2+b^2)] I still come out with an incorrect answer.

I'm wondering if the c should be included in the problem or not, but when I do input it in the Icom, it still does not work. I must be missing something important

The answer should be fitting with 4.7 x 10^-4 kg.m^2