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Rotational Inertia

  1. Mar 20, 2010 #1
    Moment of Inertia

    I need to calculate the moment of inertia of the setup below. I dont even know where to start, i have to initially calculate it without the point of masses and than with the point of masses. I have already calculated the acceleration for each of the experiments.

    I am not asking to calculate and do all the work for me, i am asking to explain or to tell me the formula which i have to choose

    The info i have is:

    Hanging mass - .050kg

    Pulley Radius - .010m

    Point of mass 1 - .250kg

    Point of mass 2 - .250kg

    Acceleration - 0.00671

    I believe the moment of inertia of the bare arm is

    I = mr²((g-a)/a)

    I = .050*.010² * ((9.8-0.00671)/0.00671)

    I = 0.000005 * 1459.51 = 0.0730

    Am i calculating this correctly?

    Attached Files:

    Last edited: Mar 20, 2010
  2. jcsd
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