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Rotational Kinematics & Energy

  1. Oct 21, 2006 #1
    A 10.7 g CD with a radius of 6.06 cm rotates with an angular speed of 30.9 rad/s. What is its kinetic energy?

    What angular speed must the CD have if its kinetic energy is to be doubled?


    Here is my work:

    kinetic energy energy = 1/2 m v2
    = 1/2 m ( r ω )2
    = 0.5 x 0.0107 x ( 0.0606 x 30.9 )^2 J

    angular speed must be increased by ( 2)^ 1/2 if kinetic energy is duobled
    since kinetice enrgy is proportional to ω2

    That answer isn't right, it comes out to be 0.188 J, can anyone tell me what is wrong with my equation?
     
  2. jcsd
  3. Oct 21, 2006 #2

    OlderDan

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    Science Advisor
    Homework Helper

    Chek your formula for the kinetic energy of a rotating rigid body. Not everything is moving with the speed you used.
     
  4. Oct 21, 2006 #3
    what is wrong with the formula? Only one speed is given.
     
  5. Oct 21, 2006 #4

    Astronuc

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    Staff: Mentor

    See this for discussion of rotational kinetic energy.

    http://hyperphysics.phy-astr.gsu.edu/hbase/rke.html

    One angular speed is given, but the local linear speed depends on r to which OlderDan alluded, i.e. v = [itex]\omega[/itex]r.

    One must use the appropriate moment of inertia for the CD.
     
  6. Oct 21, 2006 #5
    Thanks for all the wonderful help!!
     
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