- #1

- 105

- 3

## Homework Statement

A wheel of diameter 45.0 cm starts from rest and rotates with a constant angular acceleration of 2.50 rad/s2 . At the instant the wheel has completed its second revolution, compute the radial acceleration of a point on the rim in two ways.

1 Using the relationship a

_{redial}=ω

^{2}r.

2 From the relationship a

_{redial}=v

^{2}/r.

## Homework Equations

v=ωr

rotational kinematics

a

_{redial}=ω

^{2}r

a

_{redial}=v

^{2}/r.

## The Attempt at a Solution

α= 2.5

it says second rotation so θ= 2π*2 = 12.57

θ = ωt + ½ α t

^{2}

12.57 = ½ 2.5 t

^{2}

t= 3.171

ω = ω + α t

ω = 2.5 (3.171)

ω = 7.927

a

_{redial}=ω

^{2}r

a = 7.927

^{2}* 22.5 =

**1413.716694**

2 should be the same answer since the equations are equal

why is my answer wrong?