- #1

- 10

- 0

## Homework Statement

A skater spins with an angular speed of 17.4 rad/s with his arms outstretched. He lowers his arms, decreasing his moment of inertia from 43 kg/m^2 to 37 kg/m^2. Calculate his initial and final rotational kinetic energy.

## Homework Equations

L=I[tex]\omega[/tex]

KE=1/2I[tex]\omega[/tex]^2

## The Attempt at a Solution

Not sure if im on the right track here, for initial kinetic energy I came up with 3.53 J. I manipulated L=I[tex]\omega[/tex] to get [tex]\omega[/tex]=L/I to find my angular velocity. Then plugged that in the KE=(1/2)(43 kg/m^2)(.405^2) to get 3.53 J. Did I do this correctly?