I need help figuring out how much HP/TQ is freed up by changing to a lighter flywheel in a car. Specifically the Mazda KLDE/KLO3 2.5L V6 found in the Ford Probe/Mazda MX6. I have listed all needed specifications (I hope). Basically I enjoy physics but am not smart enough to identify and apply the nessecary equations to get the desired result. I know that the benifit will be proportional to acceleration and gear ratio. I hope someone can help me identify the TQ/HP freed up! Stock flywheel is 23 lbs Aftermarket flywheel is 9lbs Flywheel diameter is 250mm Redline: 7000 Peak Horsepower: 164@6000 rpm Peak Torque: 160@4800 rpm Gear Ratios 1st: 3.307 2nd: 1.833 3rd: 1.310 4th: 1.030 5th: 0.795 final: 4.388 If you need more let me know and i will provide if i can!