Rotational Mortion

1. Nov 4, 2007

sw3etazngyrl

A 40cm diameter wheel accelerates uniformly from 240rpm to 360rpm in 6.5s. How far will a point on the edge of the wheel have traveled in this time?

I think we have to use w=2pi*f?

I used that equation and plugged in w=2pi*(120rpm/0.108min)=1107.69 revolutions. I don't know where to go from there.

2. Nov 4, 2007

hotcommodity

I'm not sure what you mean by "w," if that's your omega, you'll need to use a different approach. You're given the initial angular speed, and the final angular speed in revolutions per minute. The object has a constant angular acceleration, so you can use the equations for rotational kinematics. You'll probably want to use $$\theta = .5(\omega_0 + \omega) t$$. Does that help?

3. Nov 4, 2007

sw3etazngyrl

ohh, yea, i think i get it. so the eq. would be:

theta = .5 (240 + 360)(0.108)?

4. Nov 4, 2007

hotcommodity

You've got it. Just remember to convert units if you must.

5. Nov 4, 2007

Thanks!

6. Nov 4, 2007

sw3etazngyrl

so for distance, how should i find that? my answer is in radians.

7. Nov 4, 2007

hotcommodity

Ok, so your theta is going to be in revolutions. If you want radians, you convert using the fact that 1 revolution equals $$2\pi$$ radians. Does that help?

8. Nov 4, 2007

sw3etazngyrl

yes, it does. so the 40cm is irrelevant?

9. Nov 4, 2007

hotcommodity

Well, if we were asked the linear distance traveled by the point, then it would be necessary. But if we're simply considering its angular displacement over some period of time, it's not necessary. Make sure the problem doesn't ask for linear distance.

10. Nov 4, 2007

sw3etazngyrl

it's asking for the distance the edge of wheel will be at or have traveled

11. Nov 4, 2007

hotcommodity

As in a wheel rolling across the ground?

12. Nov 4, 2007

sw3etazngyrl

i think so

13. Nov 4, 2007

sw3etazngyrl

i got it now, THANKS!

14. Nov 4, 2007

hotcommodity

You're welcome. I'd just ask that you be 100% sure it's not asking for the linear distance. If it is, you'll have to use the "rolling constraints" $$v_{linear} = \omega r, a_{linear} = \alpha r$$. If it's asking for the answer in radians or revolutions, then you're good to go, I wouldn't want you getting the wrong answer :)