- #1

cavery4

- 9

- 0

I thought to use: torque = I * alpha (acceleration)

To find Inertia, I did I = 1/2 MR^2

to find acceleration: alpha = (wf - wi)/time or 20 rad/s / .65 seconds

Also, I converted 17 g to .17 kg and 6.0 cm to .06 meters.

My answer was .942. This was marked wrong by webassign. Obviously, I am missing something here. Wrong formula? Missing an important concept? Possibly wrong calculation?

If you point me to my error, I would appreciate this greatly!

I used the above methods to find the correct answer to this problem:

The circular blade on a radial arm saw is turning at 256 rad/s at the instant the motor is turned off. In 17.0 s the speed of the blade is reduced to 80 rad/s. Assume the blade to be a uniform solid disk of radius 0.160 m and mass 0.400 kg. Find the net torque applied to the blade.

What is different about these two problems? What does the radial arm have to do with it?