A 3.3m long pole is balanced vertically on its tip. It is given a tiny push. What will be the speed of the upper end of the pole just before it hits the ground? Assume the lower end does not slip.(adsbygoogle = window.adsbygoogle || []).push({});

mgh=.5mv^2 + .5Iw^2 Initial PE = final KE translation + final KE rotational

v=rw, I=.33mr^2

Combine these equations and I got

v=(1.5gh)^(1/2)

Now I think this is the speed of the CM, located 1.65m above the ground (h=1.65). So to find the speed of the tip I covert v into radians per second and then multiply that by 3.3 to find speed of the tip.

Is this method correct? The book contains no answer.

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# Homework Help: Rotational Motion of a long pole

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