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Rotational Motion of a spindle

  1. Nov 24, 2008 #1
    1. The problem statement, all variables and given/known data
    A uniform disk turns at 9.5 rev/s around a frictionless spindle. A nonrotating rod, of the same mass as the disk and length equal to the disk's diameter, is dropped onto the freely spinning disk, see the figure. They then turn together around the spindle with their centers superposed. What is the angular velocity of the combination?




    2. Relevant equations



    3. The attempt at a solution

    I1w1= 1/2mr^2*9.5rev/sec
    I2w2= 1/12ml^2*w2
    That's as far as I got...is it even right??
     
  2. jcsd
  3. Nov 25, 2008 #2

    tiny-tim

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    Hi Bones! :smile:

    (have an omega: ω :wink:)

    Sort-of … the Is are right …

    but you need conservation of angular momentum,

    so for the "after" side, you'll need the total I, = I1 + I2, so that you can find (I1 + I22. :smile:
     
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