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A mass (m) is connected to a pulley (rotational inertia I and radius R) which sits atop an incline with angle theta find an expression for angular acceleration in terms of M I R and theta.... incline is frictionless
using T= aI
i get Rmgsin(theta) = aI so a = Rmgsin(theta) over I
but alas this isnt correct and im not sure why
the correct answer has the same numerator but the denominator is I + mR^2 where is the mR^2 coming from? THANKS for any help
using T= aI
i get Rmgsin(theta) = aI so a = Rmgsin(theta) over I
but alas this isnt correct and im not sure why
the correct answer has the same numerator but the denominator is I + mR^2 where is the mR^2 coming from? THANKS for any help