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Rotational motion

  1. Dec 28, 2015 #1
    1. The problem statement, all variables and given/known data
    http://serv1.gulfup.cc/i/00003/ev7u8r04c18k.jpg [Broken]

    2. Relevant equations
    K1+U1=K2+U2

    3. The attempt at a solution
    I have the solution i am just confused about one point,
    in the solution, it considred both the translational and rotational kinetic energy for the cylinder on the tabletop,
    but since the table is frictionless and the string is attached to its center, shouldnt it not rotate, thus only have translational energy and not rotational energy?
     
    Last edited by a moderator: May 7, 2017
  2. jcsd
  3. Dec 28, 2015 #2

    gneill

    User Avatar

    Staff: Mentor

    The problem states that the cylinder rolls without slipping. That means that the table surface is not frictionless.
     
    Last edited by a moderator: May 7, 2017
  4. Dec 28, 2015 #3
    It clearly states that the cylinder does not slip, essentially the distance traveled is only by rolling. So just consider the rotational motion.
     
  5. Dec 28, 2015 #4
    Frictionless are mechanical parts.
     
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