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Rotational problem 3

  1. Jul 24, 2013 #1
    1. The problem statement, all variables and given/known data

    A 75 g 30 cm long rod hangs vertically on a frictionless, horizontal axle passing through its center. A 10g ball of clay traveling horizontally at 2.5 m/s hits and stick to the very bottom tip of the rod. To what maximum angle measured from the vertical, does the rod with attached ball of clay rotate?

    2. Relevant equations
    Angular momentum is conserved
    initial L=final L
    mvr=Iω
    I=1/12MR^2 +mr^2
    rotational K.E=1/2 Iω^2
    MGh

    3. The attempt at a solution
    angular momentum :
    0.01(2.5)(0.3)=(I1+I2)ω
    Rod: I1=1/12MR^2=1/12(0.075)(0.15)^2=1.40e-04
    Clay: I2=mR^2=.01(0.15)^2=2.25e-4
    Initial energy =1/2 (I1+I2)ω^2

    h1=.3-.3cos∅
    mgh1=.01(9.8)(.3-.3cos∅)
    h2=.15-.15cos∅
    Mgh2=0.075(9.8)(.15-.15cos∅)
    Final energy=Mgh1+mgh2
    my question is only kinetic rotational energy is converted to potential energy and how come the kinetic energy is not converted to rotational energy and my teacher said the linear momentum is not conserved and I am so confused . Secondly, why the mass of initial angular momentum is small mass not the mass of clay and rod ?
     
  2. jcsd
  3. Jul 24, 2013 #2

    haruspex

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    Only if you choose the point to take moments about such that external forces make no contribution.
    About what point? How far is the point of impact of the clay ball from that point?
    It's 1/12 if R is the length of the whole rod. What length did you use above?
    What does h1 represent?
    You can view the clay mass after impact either as rotating about the centre of the rod (so use rotational KE) or as moving linearly horizontally (briefly). They produce the same KE. These are two different ways of looking at the same thing - don't add them.
    That's right. It obviously is not conserved during impact, and it's not conserved during the subsequent rotation either because there will be a force from the axle.
    Initial? Do you mean before or after impact? Before impact, the rod is stationary, so how would that contribute to angular momentum?
     
  4. Jul 26, 2013 #3
    I have another question if the massless rod is in that case , should I consider the Kinetic energy to be the initial energy ?
     
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