OK.hellothere123 said:ok so F = 1.5 i + 2.4 j
No, that's just the point about which you are finding the torque. [itex]\vec{r}[/itex] is the displacement from that point: r = (x2 - x1) i + (y2 - y1) jand x = -1.3 m, y = 2.4
Right.hellothere123 said:so the r displacement would be 3-(-1.3) i + 0-2.4 j
That would be the magnitude of r.so r would be sqrt( 4.3^2 + 2.4^2) ?
Take the cross-product, as I indicated in post #2.hellothere123 said:ok so since i have 4.3 i - 2.4 j how do i begin to find the torque and such?
Sounds good to me. (Don't neglect the units.)hellothere123 said:so i get 13.92 k is that right?
Torque is a measure of the force that can cause an object to rotate around an axis. It is calculated by multiplying the force applied to an object by the distance from the axis of rotation to the point where the force is applied.
The direction of torque is determined by the direction of the force applied and the direction of the lever arm, which is the perpendicular distance from the axis of rotation to the point where the force is applied. Torque direction is always perpendicular to the plane of rotation.
Clockwise torque is a rotational force that causes an object to rotate in a clockwise direction, or to the right, while counterclockwise torque causes an object to rotate in a counterclockwise, or left, direction.
Force and torque have a direct relationship, meaning that as the force applied to an object increases, so does the torque. This is because a higher force will cause a greater rotational acceleration, resulting in a larger torque.
To solve rotational problems with multiple forces and torques, you can use the principle of superposition, which states that the total torque on an object is equal to the sum of the individual torques. You can also use the equations τ = rFsinθ and τ = Iα, where τ is torque, r is the lever arm, F is the force applied, θ is the angle between the force and the lever arm, I is the moment of inertia, and α is the angular acceleration.