The pulley in the illustration is a uniform disk of mass 2.40 kg and radius 0.220 m. The block applies a contant torque to the pulley, which is free to rotate without friction, resulting in an angular acceleration of magnitude 0.180 rad/s2 for the pulley. As the block falls 0.500 m, how much work does it do on the pulley? The illustration is of a pulley with a rope hanging a block down vertically. Here is my attempt: work = torque x angular diplacement If the block falls then the pulley turns by the same amount, right? so arc length = .500m theta = arc length / radius = .500 / .220 = 2.27 radians = angular displacement?? (is this right?) To find torque, I need F x r r = .220 How do I find the Force? Do I use the mass = 2.4 kg and multiply by tangential acceleration?