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Rotationl intertial and energy

  1. Apr 6, 2013 #1
    1. The problem statement, all variables and given/known data

    A solid disk of mass 2.5 kg with a radius of 11.0cm is released from rest on an incline plane. If the plane is 1.25 m high and the angle is 25 degrees what will be the linear speed of the disk at the bottom of the incline?
    Idisk = 1/2 mr^2 and Ihoop = mr^2

    2. Relevant equations

    mgh = 1/2 mv^2 + 1/2Iw^2



    3. The attempt at a solution
    I = 1/2mr^2
    mgh = 1/2 mv^2 + 1/2(1/2mr^2)w^2

    mass cancles
    gh = 1/2 v^2 + 1/4r^2w^2

    substitute w = v/r

    gh = 1/2 v^2 + 1/4r^2(v^2/r^2)

    The radius will cancel you combine the velocity fraction get to v and you end up with something of the form

    Sqrt(4/3gh) = v
    Plug in the numbers and you get 4.04 m/s

    Is this right? Please help me double check. I felt there was a lot of information that did not get used but that doesn't mean it is not correct.
    Thanks,
    j
     
  2. jcsd
  3. Apr 6, 2013 #2

    Doc Al

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    Staff: Mentor

    Looks good to me.
     
  4. Apr 6, 2013 #3
    OK, well the more eyes the better. Thanks dude. It is just I feel he gave information to throw me off or something. I don't know.
     
  5. Apr 6, 2013 #4

    Doc Al

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    Staff: Mentor

    Part of knowing how to solve a problem is knowing what's important and what's not.

    And there are several ways to solve for the speed. What you did, solving it symbolically and only plugging numbers in at the last step, is the smart way. Someone else might have plugged numbers in at every step. The "unused" data would have been used by such a person.
     
  6. Apr 7, 2013 #5
    Yeah, It is right.
     
  7. Apr 7, 2013 #6
    Hi I have another one posted with torque and hanging a sign if someone oone could double check me it would be great. thanks for the help.
     
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