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Rough root equation, need help

  1. Dec 1, 2004 #1
    [tex]\sqrt{x} + \sqrt{x+2} + \sqrt{x}\sqrt{x+2}=16,5-x[/tex]
     
    Last edited: Dec 1, 2004
  2. jcsd
  3. Dec 1, 2004 #2

    arildno

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    Is [tex]\sqrt{x}x=x^{\frac{3}{2}}[/tex] ?
    Or is this a typo?
     
  4. Dec 1, 2004 #3

    arildno

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    Hint:
    [tex]\frac{1}{2}(\sqrt{x}+\sqrt{x+2})^{2}=x+\sqrt{x}\sqrt{x+2}+1[/tex]
     
  5. Dec 1, 2004 #4
    thanks, i knew i had to transform my initial equation to square equation over new variable, so, yes, ur hint is the key, thanks again
     
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