Hello I have a basic but quite difficult question about roulette probabilities (assuming roulette has 37 numbers 0-36). I need a general formula for calculating the probability of an event, given specific parameters:(adsbygoogle = window.adsbygoogle || []).push({});

We need to calculate the probability P(e) of the event E = [Bet B appearing X times in N trials(ie. spins) ]

We know:

N= the numbers of spins

X=the number of times a specific bet wins/appears in those N trials (spins)

P(b) = the probability of bet B for a single spin/trial.

How do we calculate the probability of [Bet B appearing X times in N trials(spins) ]?

For example what is the probability of a specific number appearing exactly 1 time in 37 spins, given it’s probability is 1/37?

What’s the formula?

Can we in the same way calculate, let’s say the probability of 12 specific numbers (probability 12/37) coming 2 times in 5 spins etc.?

I have tried to devise a formula which you can see here: http://www.roulette30.com/2014/01/calculating-probability-roulette.html

P(e) = (n!/(x!(n-x)!)) P(b)^x

But I think it is incorrect since it gives an extremely low probability of a specific number appearing exactly 1 time in 37 spins.

Maybe this is the correct formula?

P(e) = (n!/(x!(n-x)!)) P(b)^x (1-P(b))^n-x

But this again gives an extremely low probability of a specific number appearing exactly 1 time in 37 spins, if my calculations are correct.

Thanks in advance.

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# Roulette probability question

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