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Roundup Amusment Park Problem

  1. Mar 8, 2009 #1
    1. The problem statement, all variables and given/known data

    In an amusement park ride called The Roundup, passengers stand inside a 16.0 m-diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane.

    Part A: Suppose the ring rotates once every 4.10 s. If a rider's mass is 54.0 kg, with how much force does the ring push on her at the top of the ride?

    Part B: Suppose the ring rotates once every 4.10 s. If a rider's mass is 54.0 kg, with how much force does the ring push on her at the bottom of the ride?

    Part C: What is the longest rotation period of the wheel that will prevent the riders from falling off at the top?


    2. Relevant equations

    Fr=nr+(Fg)r=n+mg=mv^2/r
    w=v/r
    1 rev=2pi radians
    Might be more needed..

    3. The attempt at a solution
    4.10s/1 rev=1 rev/2pi radians=6.44 rad/s=w
    w=v/r=6.44rad/s/8m=51.52m/s
    Then do I plug it into the Fr equation? I don't have the acceleration..
    Any help or how to think about it would be advantageous.
    Thanks.
     
  2. jcsd
  3. Mar 8, 2009 #2

    Delphi51

    User Avatar
    Homework Helper

    Those calcs don't look right to me.
    You could do w = 1 rev/4.1s = 2*pi/4.1 = 1.53 radians/s
    Or just work with v = 2*pi*r/T.
    The n+mg=mv^2/r looks good.
     
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