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## Homework Statement

## Homework Equations

$$ Z(1) = \sum_{i=1}^{} e^{\frac{E_i}{K_bT}} $$ where ##E_i## is each of the possible energy states available to a single link (in this case the right and the left states).

$$ P=\frac{\sum_{i=1}^{} e^{\frac{E_i}{K_bT}}}{Z} $$

## The Attempt at a Solution

Hi all,

For part a) I obtained ## Z(1) = 2cosh(\frac{lF}{K_bT}) ## = the partition function for a single link.

For b) the probability of a single link to point to the right is: ## P=\frac{exp[\frac{lF}{K_bT}]}{2cosh(\frac{lF}{K_bT})} ##.

And for part c), the total partition function would be ##Z=[Z(1)]^N##, where ##Z(1)## is as given in the answer for part a).

Is this all correct thus far?

For part d) however I'm unsure on how to proceed. Any ideas?