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Rubber band thermodynamics

  1. Nov 10, 2009 #1
    1. The problem: Suppose a rubber band obeys the equation of state: L = f (b/T), where L is length, f is tension, b is a constant, and T is temperature. For this rubber band, determine (δCL/δL)T, i.e. the change in the constant length heat capacity with length at constant temperature. You should be able to determine this using the following Maxwell Relation: (δf/δT)L = - (δS/δL)T, where S is the entropy



    2. equations: dS = [(δS/δL)T]dL + [(δS/δT)L]dT
    The constant length heat capacity, CL = T[(δS/δT)L]




    3. Attempt: since L = f (b/T), TL = fb, and d(TL) = d(fb). b is constant, and hold L constant and use chain rule to get LdT = bdf. This implies that (δf/δT)L = L/b. Using the Maxwell relation, this implies that L/b = - (δS/δL)T. Also, using the equation of state, L/b = f/T, so - (δS/δL)T = f/T also. As mentioned above, dS = [(δS/δL)T]dL + [(δS/δT)L]dT. [(δS/δL)T] = - f/T, and [(δS/δT)L] is the constant length heat capacity divided by T, [CL]/T. Since dS is an exact differential, another Maxwell relation results from this: [(δ[[CL]/T]/δL)[SUB]T] = -[(δ(f/T)/δT)[SUB]L]. Using the chain rule, I got that (δC[SUB]L/δL)[SUB]T = f/T - 1

    I hope this is clear enough. Let me know if I need to clarify anything. Second opinions would be greatly appreciated! Thanks[/SUB][/SUB][/SUB][/SUB]
     
  2. jcsd
  3. Nov 11, 2009 #2

    Mapes

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    Isn't

    [tex]-\left(\frac{\partial(f/T)}{\partial T}\right)_L=-\left(\frac{\partial(L/b)}{\partial T}\right)_L[/tex]

    equal to zero? And since you have this as equal to

    [tex]\left(\frac{\partial(C_L/T)}{\partial L}\right)_T=\frac{1}{T}\left(\frac{\partial C_L}{\partial L}\right)_T[/tex]

    would the change in the constant-length heat capacity with length at constant temperature also be zero?
     
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