# Rudin 8.10

[SOLVED] rudin 8.10

## Homework Statement

Prove that $(1-x)^{-1} \leq \exp 2x[/tex] when [itex]0 \leq x \leq 1/2$.

## Homework Equations

$$e^x = \sum_{i=0}^{\infty}\frac{x^n}{n!}$$

$$1/(1-x) = 1+x+x^2+\cdots$$

## The Attempt at a Solution

I tried working with the series and that failed miserable. Maybe I need to use calculus and find out whether the function is increasing or decreasing but I started that but I tried that a little and did not see how it would help.

HallsofIvy
Homework Helper
1. What are their values when x= 0?

2. How do their derivatives compare?

1. What are their values when x= 0?
They are both 1.

2. How do their derivatives compare?

Let f(x) = 1/(1-x) and g(x) = e^{2x}.

Then $f'(x) = 1/(1-x)^2$ and $g'(x) = 2 e^{2x}$.

Is there an obvious inequality between f'(x) and g'(x) when $0 \leq x \leq 1/2$? I do not see it.

MathematicalPhysicist
Gold Member
well I think it's best to evaluate:
(e^(2x)(1-x))=f(x)

and to find where is its minimum point in the interval: [0,1/2]

Yay, I got it thanks!