Prove Russel's paradox by contradiction and what does it tell us about sets?(adsbygoogle = window.adsbygoogle || []).push({});

I tried doing it like this and I am not sure it is right.

I supposed S was the collection of all sets and since S is a set S∈S.

Now we can split this universe S into two parts: U(for the unusual that are part of themselves like S) and N(for the normal sets).

So N={A∈S|A∉A}. In english this means that any set A will be part of N only if A is not an element of itself.

Now I plug in N in place of A, to apply the above statement for N.

N={N∈S|N∉N}.

So since N is not an element of itself, N belongs in N.

Is it correct ^?

Also what does this tell us about sets?

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Khadija Niazi

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# Russel's paradox

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