1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rutherford scattering

  1. Feb 28, 2005 #1
    A) While reproducing the Rutherford scattering experiment in an advanced laboratory class, a student uses a gold foil with thickness 16.7 nm. The radioactive source emits a particles at 10.50 MeV, and the detector is placed at 24.5 cm from the target foil. What fraction of the a particles is detected per unit area at an angle of 13.6 degrees?

    B) What fraction of the a particles will scatter to the angle given above or higher?

    A .. fraction/area = N(theta) / Ni ...n = #/volume ...n = 5.90*10^22 ...dont really no where to go from here ... i have the equation Ntheta = Ni(n)(t)/16 r^2 (rmin)^2 1/(sin^4 theta/2)
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you help with the solution or looking for help too?
Draft saved Draft deleted



Similar Discussions: Rutherford scattering
Loading...