Rutherford's Gold Foil Alpha Particle Interactions

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In summary, if an alpha particle comes into contact with an electron in a gold atom, it will be ejected and will convert to helium. There is a chance of transmutation occurring if alpha particles are present in an atmosphere or vacuum, but it is very rare.
  • #1
Kalyan Mokirala
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Hi All,
I am asking this question as a lay man based on the questions which my 10 year old kid raised while explaining alpha ray scattering experiment.
As Alpha particle is a high energetic particle when it interacts with electron of gold atom it ejects the electron. Is there any probability if getting an alpha particle converted to Helium during such interaction?
In fact when alpha particles comes to rest it will attract 2 electrons becoming helium. What happens to alpha particle if it is present in inert atmosphere/Vacuum having no electrons?
Are there any chances of artificial transmutation during the interaction of alpha particle with the nucleus of gold?
 
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  • #2
Once an Alpha Particle slows down, it will always become a Helium Atom, eventually as it is doubly charged and will attract nearby free electrons. The total number of electrons in the (neutral) equipment or the lab will always be the same as the number of protons so that process is inevitable. Imagine an alpha particle bumping into a piece of metal. There are vast numbers of electrons floating around in the metal lattice and anyone of them would attach to the alpha particle. That whole piece of metal would have a net charge of +2e, which is negligible.
The energy needed for transmutation can be high and it's neutrons that are responsible for fission in reactors, I believe. But there are fission products that, in themselves, are very unstable and they will decay spontaneously, left to themselves So an alpha particle could well cause fission in that case. The basics of nuclear reactions in stars involves alpha particles and others, colliding to form heavy nuclei. See this link. There is a limit (Iron) to the size of nucleus that can be formed in a star because of the energy available. Heavier nuclei have to be formed in Supernovae where there is more energy available.
 
  • #3
The scattering experiment is about the scattering of the alpha particles themselves.

Ionizing radiation has enough kinetic energy to knock electrons from whatever they go through.

An alpha particle is a Helium nucleus
 

1. What is Rutherford's Gold Foil Experiment?

Rutherford's Gold Foil Experiment, also known as the Geiger-Marsden Experiment, was a landmark experiment in the field of nuclear physics conducted by Ernest Rutherford in 1909. It involved shooting alpha particles at a thin sheet of gold foil and observing their interactions, which led to the discovery of the atomic nucleus.

2. What was the purpose of Rutherford's Gold Foil Experiment?

The purpose of this experiment was to investigate the structure of the atom and determine the distribution of positive and negative charges within it. At the time, the popular "plum pudding" model of the atom proposed that the positive and negative charges were evenly distributed throughout the atom. Rutherford's experiment aimed to test this model and provide a better understanding of the atom.

3. How did Rutherford's Gold Foil Experiment disprove the plum pudding model?

The results of the experiment showed that most of the alpha particles passed straight through the gold foil, but a small percentage were deflected at large angles or even bounced back. This could not be explained by the plum pudding model, which predicted that all particles would pass through the gold foil without any deflection. Rutherford concluded that the atom must have a small, dense, positively charged nucleus to cause the deflections of the alpha particles.

4. What are the implications of Rutherford's Gold Foil Experiment?

This experiment revolutionized the understanding of atomic structure and led to the development of the modern model of the atom. It also paved the way for further discoveries in nuclear physics and the development of nuclear energy. Additionally, Rutherford's experiment provided evidence for the existence of isotopes, which are atoms of the same element with different numbers of neutrons.

5. How is Rutherford's Gold Foil Experiment still relevant today?

Rutherford's experiment is still relevant today because it laid the foundation for our understanding of atomic structure and the behavior of subatomic particles. It also continues to be studied and replicated in various forms to further advance our knowledge of nuclear physics. Additionally, the experiment's findings have practical applications in fields such as medicine, energy production, and materials science.

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