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- Thread starter Silviu
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mfb

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So from the point of view of the S matrix, an interacting particle with momentum p and a non-interacting particle with momentum p are identical at ##\pm \infty##? But the operators used to create a particle with momentum p i.e. ##a_p^\dagger## is different (they evolve differently in time) in the 2 theories as the vacuum is different?

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This may be of interest to you https://en.m.wikipedia.org/wiki/Haag's_theorem

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The conceptual framework of QFT, Oxford University Press

It's precisely filling the gaps Weinberg's three volumes leave.

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Page 3 said:'the description of such a process as occurring in the course of time is therefore just as unreal as the classical paths are in non-relativistic quantum mechanics. The only observable quantities are the properties of free particles'

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