Sailboat and wind accel.

1. Jun 22, 2007

ere

1. The problem statement, all variables and given/known data
A sailboat is travelling east at 4.5ms-1. a suddent gust of wind gives the boat an acceleration a = 0.70 ms-2, 40 degress north to east. what are the boat's speed and direction 6s later when the gust subsides?

2. Relevant equations
V(@6s) = V(init.) + at

3. The attempt at a solution
i seriously have not a clue where to start. tried to look it up in books and online but i still dont know what to do with the acceleration.
so the a(x) = 0.70cos40 V(x) = 4.5
a(y) = 0.70sin40 V(y) = 0 am i right?​
thus, V(6s)(x) = 4.5 + .070cos40(6) = 7.7174
V(6s)(y) = 0 + 0.70sin40(6) = 3.8567​
therefore, direction n in degree:
tan(n) = 3.8567 / 7.7174, n = 26.55 degrees​
velocity = (7.7174^2 + 3.8567^2)^(1/2) = 8.6274​
and i am told that i am wrong. hope you guys can point out why. thanks!

Last edited: Jun 22, 2007
2. Jun 22, 2007

Staff: Mentor

It does not appear to me that you have enough inforation to solve the problem. You need the time of the acceleration.

Unless it is a trick question and the answer is 4.5m/s, East....

Anyway, your analysis is certainly wrong as you are mixing velocity and acceleration.

3. Jun 22, 2007

ere

oops sorry i left that out. just edited the thread.

4. Jun 22, 2007

Staff: Mentor

Well, then the answer is that you mixed acceleration and speed. You need to use the acceleration and the time to calculate the magnitude of the second speed vector before adding the two vectors together.

5. Jun 22, 2007

hardyivan007

What is wrong? and Where? What do you mean by confusing velocity and acceleration? Find the effective acceleration for both Y and X axis, then use the
linear laws of motion to get the final velocity components? Why is this wrong?

6. Jun 22, 2007

hardyivan007

This calculation seems to have error