- #1
ere
- 9
- 0
Homework Statement
A sailboat is traveling east at 4.5ms-1. a suddent gust of wind gives the boat an acceleration a = 0.70 ms-2, 40 degress north to east. what are the boat's speed and direction 6s later when the gust subsides?
Homework Equations
V(@6s) = V(init.) + at
The Attempt at a Solution
i seriously have not a clue where to start. tried to look it up in books and online but i still don't know what to do with the acceleration.
so the a(x) = 0.70cos40 V(x) = 4.5
a(y) = 0.70sin40 V(y) = 0 am i right?
thus, V(6s)(x) = 4.5 + .070cos40(6) = 7.7174V(6s)(y) = 0 + 0.70sin40(6) = 3.8567
therefore, direction n in degree:tan(n) = 3.8567 / 7.7174, n = 26.55 degrees
velocity = (7.7174^2 + 3.8567^2)^(1/2) = 8.6274
and i am told that i am wrong. hope you guys can point out why. thanks!
Last edited: