1. The problem statement, all variables and given/known data A sailboat is travelling east at 4.5ms-1. a suddent gust of wind gives the boat an acceleration a = 0.70 ms-2, 40 degress north to east. what are the boat's speed and direction 6s later when the gust subsides? 2. Relevant equations V(@6s) = V(init.) + at 3. The attempt at a solution i seriously have not a clue where to start. tried to look it up in books and online but i still dont know what to do with the acceleration. so the a(x) = 0.70cos40 V(x) = 4.5 a(y) = 0.70sin40 V(y) = 0 am i right?thus, V(6s)(x) = 4.5 + .070cos40(6) = 7.7174 V(6s)(y) = 0 + 0.70sin40(6) = 3.8567therefore, direction n in degree: tan(n) = 3.8567 / 7.7174, n = 26.55 degreesvelocity = (7.7174^2 + 3.8567^2)^(1/2) = 8.6274and i am told that i am wrong. hope you guys can point out why. thanks!