- #1

vane12

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A sailboat race course consists of four legs defined by the displacement vectors A, B, C and Dshown above.

The values of the angles are Θ1 = 35.00, Θ2 = 34.00, andΘ3 = 20.00.

The magnitudes of the first three vectors are A = 3.0 km, B = 5.0 km and C = 4.5 km. The finish line of the course coincides with the starting line.

The coordinate system for this problem has positive x to the right, positive y as up and counter-clockwise to be a positive angle.

1) What is the distance of the fourth leg?

2) What is the value of Θ4?

3) What is the value of Dy?

To solve the problem I did the following:

Ax = 3cos35°

Ay = 3sin35°

Bx = 5cos146°

By = 5sin146°

Cx = 4.5cos 20°

Cy = 4.5sin20°

Somehow I was able to get the right answer of the fourth leg but not for Dy or the angle.

The values of the angles are Θ1 = 35.00, Θ2 = 34.00, andΘ3 = 20.00.

The magnitudes of the first three vectors are A = 3.0 km, B = 5.0 km and C = 4.5 km. The finish line of the course coincides with the starting line.

The coordinate system for this problem has positive x to the right, positive y as up and counter-clockwise to be a positive angle.

1) What is the distance of the fourth leg?

2) What is the value of Θ4?

3) What is the value of Dy?

To solve the problem I did the following:

Ax = 3cos35°

Ay = 3sin35°

Bx = 5cos146°

By = 5sin146°

Cx = 4.5cos 20°

Cy = 4.5sin20°

Somehow I was able to get the right answer of the fourth leg but not for Dy or the angle.