Same product, different loops

[magnifik]

I am trying to create a code that does the exact same thing as this does

#include <iostream>
	using namespace std;

	int main()
	{
	    int len;

	    cout << "Enter a number: ";
	    cin >> len;

	    for (int i = 0; i < len; i++)
	    {
		for (int j = i+1; j < len; j++)
		{
		    cout << ' ';
		}
		cout << "#\n";
	    }
	}

but using a do while loop instead. what i have so far is this

#include <iostream>
	using namespace std;

	int main()
	{
	    int len;

	    cout << "Enter a number: ";
	    cin >> len;
			
	    for (int i = 0; i < len; i++)
	    {
			int j = i+1;
			do
			{
				cout << ' ';
				j++;
			}
		while (j < len);
		cout << "#\n";
		}
	}

the only problem is on the last line the "#" signs line up instead of being diagonal. any help on how to fix this??

 

[kentigens]

try put a if condition insdie the do while loop instead just cout outside while loop. could use conditions like if j = len -1, then cout the #

 

[magnifik]

try put a if condition insdie the do while loop instead just cout outside while loop. could use conditions like if j = len -1, then cout the #

hmm, not exactly sure what you mean. the closest i got was adding

 if (j == len -1) {
           cout << "#";
           }

into the do part of the do while loop, but this just created two side by side diagonal lines :T to top line had len - 1, but the bottom line had the correct shape and number. any idea on how to get rid of the first one?

 

[kentigens]

i mean to take out the line where u cout the # from ur original code. and btw, don't have vs here, so can't really run ur code. can u please post up the outputs? both original code and the one u have atm?

 

[DeeNos]

I would suggest using a nested do-while loop to achieve the same result as the original code. This would involve using a do-while loop inside the for loop, similar to how the for loop is nested inside the for loop in the original code.

The code could look something like this:

#include <iostream>
using namespace std;

int main()
{
int len;

cout << "Enter a number: ";
cin >> len;

for (int i = 0; i < len; i++)
{
int j = 0;
do
{
if (j < len - i - 1) //to create the diagonal effect
cout << ' ';
else
cout << "#";
j++;
}
while (j < len);
cout << "\n";
}
}

This way, the do-while loop will iterate through each column and check whether the current column should have a space or a "#" printed. This should result in the same diagonal pattern as the original code.