# SAT II physics light question

• oceanflavored
In summary, when monochromatic light passes through a double slit, a bright fringe is formed due to a path difference of 1 "wavelength symbol". This is determined by the equation lambda/d = x/L, where lambda is the wavelength of the light, d is the distance between the slits, x is the distance of the bright fringe, and L is the distance of the screen from the slits. This means that the answer is E) 1 "wavelength symbol". The double slit does play a role in this phenomenon and the values of x and L are not necessary to determine the answer.

## Homework Statement

When monochromatic light passes through a double slit, a bright fringe is formed due to a path difference of
A) 1/4 "wavelength symbol"
B) 1/2 "wavelength symbol"
C) 3/4 "wavelength symbol"
D) 7/8 "wavelength symbol"
E) 1 "wavelength symbol"

gracias :)

You need to make at least some effort. What have you studied in class on this topic?

Start with the definitions(what do monochromatic and slit imply?) and equations to solve this problem. Also, the wavelength symbol is the greek symbol lambda.

for maxima (bright fringe)
lambda / d = x/L
where lambda is wavelength, d is distance between slits, x is distance of bright fringe, L is distance of screen from slits.

lamda = xd/L

for bright fringe, path diff is n*lambda
for dark band, it is (2n - 1)*lambda/2

cristo said:
You need to make at least some effort. What have you studied in class on this topic?

this is a question that was in my REA SAT II physics book. we never studied this in my physics class a year ago. and there's no mention of it in my REA book. or other study books i have.

spideyunlimit said:
for maxima (bright fringe)
lambda / d = x/L
where lambda is wavelength, d is distance between slits, x is distance of bright fringe, L is distance of screen from slits.

lamda = xd/L