- #1

- 6

- 0

a) (3x+3y+4)/3

b) (2x-2y-4)/3

c) (6-2x-2y)/3

d) (x+y+6)/3

e) (3x+2y+6)/3

I'm jux wondering hwo can u do this by using PLUG INS... thanks a lot... btw the answer is D.

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- #1

- 6

- 0

a) (3x+3y+4)/3

b) (2x-2y-4)/3

c) (6-2x-2y)/3

d) (x+y+6)/3

e) (3x+2y+6)/3

I'm jux wondering hwo can u do this by using PLUG INS... thanks a lot... btw the answer is D.

- #2

Staff Emeritus

Science Advisor

Gold Member

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But if you're dead set on plugging things into solve the problem... then do it by plugging things in. :tongue: If you're having problems, then show us what you've done, and where you're stuck!

- #3

- 6

- 0

for ppl whoz orignally, i put 20 for that, then for x i put 3, and for y i put 4.

so first stop itz 20+3,

second stop itz 23+4,

third 27 * (1/3) = the ppl whoz left in the bus

fourth 9+2

so the total number is 11, but i couldn't find the answer... help! i think i have a problem about setting the original number of the bus.

- #4

Staff Emeritus

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Ah, that's your problem. The bus shouldn't have any passengers on boardfor ppl whoz orignally, i put 20 for that

- #5

- 6

- 0

so it should be 0 for the orignally passenger?

- #6

Staff Emeritus

Science Advisor

Gold Member

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I highly recommend you solve it by seeing how many passengers there must be in terms of x and y directly, otherwise you're going to be using a weak method that will only fail you later (or if it's not multiple choice)

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