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Satelite orbit distance

  1. Sep 21, 2012 #1
    1. The problem statement, all variables and given/known data
    A 320kg satellite experiences a gravitational force 800N. What is the radius of the satellite's orbit?


    2. Relevant equations
    G m1m2 / d^2


    3. The attempt at a solution
    I started with

    800N = (G(320kg)(5.98(10^24)kg) / d^2

    After some algebra and rounding I ended up with d = 40,000 km. Is that reasonable?
     
  2. jcsd
  3. Sep 21, 2012 #2
    when I put 40,000 km into the original equation and solve for the force I get around 79.77N

    what value did you use for G?
     
  4. Sep 21, 2012 #3
    I think the standard for any calculations in classical mechanics is kg and meters. So perhaps if you try 40,000,000m.

    I used 6.67 x 10 ^-11 for G.
     
  5. Sep 22, 2012 #4
    Shameless bump. Still need help.
     
  6. Sep 22, 2012 #5
    I kept trying again and again but I am getting 12k kilometers

    [itex]d = \sqrt{\frac{GMm}{F}}[/itex]

    yes?

    so


    [itex]d = \sqrt{\frac{(6.67*10^{-11}N*(\frac{m^{2}}{kg^{2}}))(5.98*10^{24}kg)(320kg)}{800 N}} = 1.26*10^{7} m[/itex]

    maybe you can point out where our calculations differ? I might be doing something hilariously incorrect.
     
  7. Sep 22, 2012 #6
    No, you're right. I re-did the calculation again and paid proper attention to parenthesis this time. I'm just not calculator savvy at all.
     
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