• Support PF! Buy your school textbooks, materials and every day products Here!

Satellite Gravitation

  • Thread starter Sheneron
  • Start date
360
0
1. Homework Statement
A 500 kg satellite is in a circular orbit at an altitude of 500km above the Earth's surface. Because of air friction, the satellite eventually falls to the Earth's surface where it hits the ground with a speed of 2000 m/s. How much energy was transformed to internal energy by means of friction.

3. The Attempt at a Solution

Ki + Ui = Kf + Uf loss

[tex]-\frac{\frac{1}{2}GM_SM_E}{Ri} = \frac{1}{2}M_SV_f^2 - \frac{\frac{1}{2}GM_SM_E}{Rf}+ loss[/tex]

[tex]-\frac{\frac{1}{2}(6.67e-11)(500)(5.98e24)}{6.37e6 + 500,000} - \frac{1}{2}(500)(2,000)^2 +\frac{\frac{1}{2}(6.67e-11)(500)(5.98e24)}{6.37e6} = loss[/tex]



Is this how to go about this problem, or did I miss a concept at the beginning? thanks
 
Last edited:

Answers and Replies

360
0
Is this the right process?
 
alphysicist
Homework Helper
2,238
1
Hi Sheneron,

I don't believe the factor of 1/2 should be in your expression for Uf.
 

Related Threads for: Satellite Gravitation

  • Last Post
Replies
9
Views
782
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
1
Views
831
  • Last Post
Replies
2
Views
6K
Top