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Satellite & Gravity

  • Thread starter pluke100
  • Start date
  • #1
11
0

Homework Statement



It is proposed to place a communications satellite in a circular orbit rounf the equator at a height og 3.59 x 10^7m above the earth's surface. Find the period of revolution of the satellite in hours and comment on result.

Values given:
Radius of Earth: 6.37 x 10^6m
Mass of Earth: 5.98 x 10^24kg
Gravitational Constant: 6.67x10^-11 m^3 kg^-1 s^-2

Homework Equations



Not sure which one you can you, but i think two different ones have to be used

The Attempt at a Solution



This is the only question which i couldn't answer, and when i tried several ways out, it got very far away from result. the answer should be :24 hrs
 

Answers and Replies

  • #2
rsk
163
5
You know that the centripetal accelration is provided by the gravitational force.

So,

mr(omega)^2 = GMm/r^2

SO you can calculate omega, the angular velocity.

Then you should have an equation relating the period tn the angular velocity.
 
  • #3
11
0
thx, i'll try it out. If i get wrong result, i'll post my working to see what's wrong
 

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