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Satellite time delay question

  1. Sep 21, 2015 #1
    1. The problem statement, all variables and given/known data

    Question: If a broadcast of a sporting event went up to a geostationary satellite, then traveled 50 000 km to another geostationary satellite, then came back to earth, what would be the delay in the signal? All electromagnetic waves travel at the speed of light, and most of the route would be in a vacuum. Also, remember that the path starts and ends at at the Earth's surface, not at the center of the Earth.

    Variables:

    c = 299 792 458 m / s
    distance between two satellites = 50,000 km or 5.0 x 10^7 m

    Other variables:

    G = 6.674 x 10 ^ -11 m ^3 / kg/
    Me (mass of earth) = 5.97219 x 10^ 24 kg
    sd (Seconds in a day) = 86400 seconds



    2. Relevant equations


    L= 2 * pi *r

    L = V/T

    V = sqrt(G * Me / r)

    From those the equation below is derived....

    r = ((sd * sqrt(G * Me)) / (2 * pi) )^ (2/3)

    v = d/t

    3. The attempt at a solution

    I found that the geostationary radius (r_) is 4.22 x 10^ 7 m or 4.22 x 10^4 km. Which is confirmed is confirmed correct.

    My problem is I don't know where to go from here I'm assuming I have to use the geostationary radius (r_) calculated and the speed of light (c). So the formula V=D/T should be the one to use.

    The answer is supposed to be 0.40 seconds

    I thought that I might need to look for the hypotenuse so I tried the a^2 + b^2 = c^2 Using 4.22 x 10^7 as a and 5.0 x 10^7 as b. I end up getting 6.54 x 10 ^ 7 m. I then took that and plugged it into the V=D/T equation to solve for T. V = speed of light.

    T = 6.54 x 10 ^ 7 / 3.0 x 10 ^ 8 = 0.218 seconds

    Unfortunately I come out with 0.218 seconds not even close to the answer.

    Where do I go from here? Thanks!
     

    Attached Files:

  2. jcsd
  3. Sep 21, 2015 #2

    SteamKing

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    Staff Emeritus
    Science Advisor
    Homework Helper

    Read the problem statement again carefully.

    The signal is transmitted from the surface of the earth to a satellite in geosynchronous orbit. The signal then bounces off that first satellite over to another satellite which is located 50,000 km away from the first satellite, and which is also in geosynchronous orbit. The signal then travels back to the surface of the earth. The total time delay is how long it takes the signal to travel over these three legs combined.
     
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