Satellites again

  • Thread starter six789
  • Start date
  • #1
127
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here is another problem...
a 650kg satellite is to be placed into synchronus orbit around Earth.
What amount of work must be done onthe satellite to raise it into synchronous orbit?

i did..
W=GMm(1/r of Earth - 1/r of synchronous satellite)
= 6.673x10^-11N m^2/kg^2 (5.98x10^6kg)(650kg)(1/6.38x10^6m - 1/4.22x10^7m)
W = 3.442998737X10^10 J

the right answer is 3.7x10^10 J... is ther something wrong with the significant digits?? can anyone tell me the mistake that i did?
 

Answers and Replies

  • #2
617
1
six789,

What kind of energy did you calculate for the satellite? Does it have any other kind when it's in orbit?
 
  • #3
127
0
a) the gravitational potential energy is -4.1x10^10 J
b) the total enrgy is -3.1x10^9 J

d) the kinetic enrgy is 3.1x10^9 J
 
  • #4
2,210
1
The kinetic energy in this case is not the same as the potential energy. The only time kinetic energy = Potential energy is when the change in kinetic energy is caused by a change in potential energy. In this case, the potential energy is always cosntant as in a circular orbit, the satelite is always the same distance from the earth.
 
  • #5
127
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i get the right answer from doc al... he said that...
change of energy = Work-Energ(total)

change=work
therefore.. Work = Work-E
=3.442998737X10^10 J - (-3.1x10^9 J)
=3.75x10^10J..
so the answer is right!!!

thanks again for the help...
 

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