here is another problem... a 650kg satellite is to be placed into synchronus orbit around Earth. What amount of work must be done onthe satellite to raise it into synchronous orbit? i did.. W=GMm(1/r of Earth - 1/r of synchronous satellite) = 6.673x10^-11N m^2/kg^2 (5.98x10^6kg)(650kg)(1/6.38x10^6m - 1/4.22x10^7m) W = 3.442998737X10^10 J the right answer is 3.7x10^10 J... is ther something wrong with the significant digits?? can anyone tell me the mistake that i did?
six789, What kind of energy did you calculate for the satellite? Does it have any other kind when it's in orbit?
a) the gravitational potential energy is -4.1x10^10 J b) the total enrgy is -3.1x10^9 J d) the kinetic enrgy is 3.1x10^9 J
The kinetic energy in this case is not the same as the potential energy. The only time kinetic energy = Potential energy is when the change in kinetic energy is caused by a change in potential energy. In this case, the potential energy is always cosntant as in a circular orbit, the satelite is always the same distance from the earth.
i get the right answer from doc al... he said that... change of energy = Work-Energ(total) change=work therefore.. Work = Work-E =3.442998737X10^10 J - (-3.1x10^9 J) =3.75x10^10J.. so the answer is right!!! thanks again for the help...