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Scales (check work)

  1. Feb 5, 2004 #1
    A block of iron is suspended from one end of an equal-arm balance by a thin wire. To balance the scales, 2.35 kg are needed on the scale pan at the other end.
    (a) What is the vloume of the block?
    (b) Next a beaker of water is placed so that the iron block is submerged in the beaker but not touching the bottom. What mass is now necessary to balance the scales?

    What I did:
    density of iron = 7.87 * 10^3 kg/m^3
    a) 2.35/[itex] \rho_{\text{iron}} [/itex] = V = 299 cm^3
    b) V = V of displaced water = m of water in grams
    2.35 kg - 299 g = 2.05 kg
  2. jcsd
  3. Feb 6, 2004 #2


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    Looks good to me.
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