Is entangle enough to find that given states have Schmidt decomposition?
Why didn't anyone reply me?
Schmidt decomposition is a usefull tool for bipartite systems: if it admits a decomposition with more than one Schmidt coefficient, then the overall state is an entangled one. So every bipartite state has a Schmidt decomposition, but only if it's entangles there's more than one coefficinet in the expansion.
are you cute? you waited 6hours only?
I'm sorry you waited so long, but I just signed in yesterday and life is so involving that someone sometimes has to wait a little...:-)
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