Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Schwarzenchild vs Minkowski

  1. Jul 17, 2013 #1
    The Schwarzenchild Metric can be the Minkowski Tensor with the correct terms in 4-Space. If not Schwarzenchild Metric must have EigenValues are all real and the Matrix is symmetrical.
     
  2. jcsd
  3. Jul 17, 2013 #2

    WannabeNewton

    User Avatar
    Science Advisor

    I'm not really sure what it is you're saying but if you're asserting that there exists a coordinate system in which the Schwarzschild metric becomes the Minkowski metric everywhere on the open subset the chart is defined on then that's obviously false; Schwarzschild space-time is not flat. What you can do is put the Schwarzschild metric in Minkowski form at a given point; this is a simple consequence of the spectral theorem.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Schwarzenchild vs Minkowski
  1. Minkowski space (Replies: 28)

  2. Minkowski Force (Replies: 3)

  3. Minkowski vs Loedel (Replies: 0)

Loading...