Secant, tangent

1. Jan 25, 2012

bobsmith76

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

I don't see how they get from step one to two. I would think both secants would cancel since one is positive and the other is negative but that doesn't happen. i think i understand the manipulations of the tangents but not entirely

2. Jan 25, 2012

issacnewton

its simple. just expand the numerator and then take sec x common

3. Jan 25, 2012

bobsmith76

ok, I get it

ab - ac = a(b-c)