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Second bright fringe in Young's Experiment
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[QUOTE="kuruman, post: 6813759, member: 192687"] The proper way to count fringes is by considering the central maximum to be the zeroth maximum. When interference is constructive and you divide the path length difference from the slits by the wavelength, you get an integer. This integer is ##n## which is zero at the central maximum because the path lengths are equal. Thus the counting is Central maximum ##n = 0## First two maxima ##n = ± 1## Second two maxima ##n = ± 2## ##\dots## I think you should use ##n=2##. [/QUOTE]
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Second bright fringe in Young's Experiment
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