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## Homework Statement

Find the second derivative of 3sec[tex]\sqrt{x}[/tex]

## Homework Equations

derivative of sec u = secu(tanu)*u'

product rule- (F*G)'=f'*g+g'*f

quotient rule- (F/G)'=(f'*g-f*g')/g^2

## The Attempt at a Solution

So i did the first derivative of it, getting 3sin[tex]\sqrt{x}[/tex]/{2[tex]\sqrt{x}[/tex]*cos^2[tex]\sqrt{x}[/tex]}

After this point, I started to simply take this derivative again. However, my paper says to find d^2y/d^2x, which is confusing to me since there is no y term in this, so is it just simply taking the derivative twice?