Implicit Diff: Find 2nd Deriv of x^3 + y^3 = 1

In summary, implicit differentiation is a method used in calculus to find the derivative of a function that is not explicitly written in terms of the independent variable. To find the second derivative using this method, the first derivative is first found using the chain rule, and then differentiated again using the product rule and chain rule. The derivative of a function, such as x^3 + y^3 = 1, can be found using implicit differentiation by treating y as a function of x and applying the chain rule to the y^3 term. To solve for dy/dx in implicit differentiation, the dy/dx term is isolated and divided by the remaining terms, while using the chain rule and product rule. Implicit differentiation can be used on any function where
  • #1
Jacob959
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Homework Statement


Find the second derivative of x^3+y^3=1 by implicit differentiation.

The Attempt at a Solution


I found the first derivative to be x^2/y^2. Do I then use the first derivative and take the derivative of that? I tried to do this, but got stuck on what to do.
 
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  • #2
Welcome to PF, Jacob959! :smile:

Your first derivative should be -x^2/y^2.

And yes, you should take the derivative from that.
Where did you get stuck?
 

1. What is implicit differentiation?

Implicit differentiation is a method used in calculus to find the derivative of a function that is not explicitly written in terms of the independent variable. It involves treating the dependent variable as a function of the independent variable and using the chain rule to find the derivative.

2. How do you find the second derivative using implicit differentiation?

To find the second derivative using implicit differentiation, you first find the first derivative using the chain rule. Then, you differentiate again using the product rule and the chain rule. Remember to keep the variables separate and use the chain rule for each term.

3. What is the derivative of x^3 + y^3 = 1?

The derivative of x^3 + y^3 = 1 is 3x^2 + 3y^2 * dy/dx = 0. This is found using implicit differentiation by treating y as a function of x and applying the chain rule to the y^3 term.

4. How do I solve for dy/dx in implicit differentiation?

To solve for dy/dx in implicit differentiation, you isolate the dy/dx term on one side of the equation and then divide by the remaining terms. Remember to use the chain rule and product rule when differentiating.

5. Can implicit differentiation be used on any function?

Yes, implicit differentiation can be used on any function, as long as the dependent variable is a function of the independent variable. It is especially useful for finding the derivatives of implicit functions, such as curves or surfaces defined by equations.

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