(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

y(x) = exp (-([tex]\sqrt{ms}/2t[/tex]) x[tex]^{2}[/tex])

Find the y"(x)

3. The attempt at a solution

y'(x) = (-([tex]\sqrt{ms}/2t[/tex]) 2x) exp (-([tex]\sqrt{ms}/2t[/tex]) x[tex]^{2}[/tex])

y"(x) = (-([tex]\sqrt{ms}/t[/tex])) exp (-([tex]\sqrt{ms}/2t[/tex]) x[tex]^{2}[/tex]) + (([tex]ms/4t^{2}[/tex])4x[tex]^{2}[/tex]) exp (-([tex]\sqrt{ms}/2t[/tex]) x[tex]^{2}[/tex])

This is correct? Sorry if it looks a bit messy... Thanks.

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# Homework Help: Second Differential

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