- #1
svenvbins
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Hi all,
I'm studying for my Quantum Optics exam and still have problems with the second-order correlation function.
The question concerned is question 3b, 3c etc which can be found here: http://www.arago.utwente.nl/comms/sotn/tentamendatabase/optics/qo/351500_Quantum_Optics_2010-11-03.pdf
They want to know [itex]g^{(2)}(\tau)=\frac{<I(t) I(t+\tau)>}{<I(t)><I(t+\tau)>}[/itex]
For [itex]\tau=0[/itex], this simplifies to [itex]\frac{<I(t)^2>}{<I(t)>^2}[/itex]
For [itex]\tau=1[/itex], it is [itex]\frac{I(t)I(t+1)>}{<I(t)><I(t+1)>}[/itex]
Now, I'd say that in the second case, the answer depends on time, since (take t=1) I(1) is not equal to I(2).
If anyone can help me out (especially understanding what exactly is going on) I'd be grateful!
Sven
I'm studying for my Quantum Optics exam and still have problems with the second-order correlation function.
The question concerned is question 3b, 3c etc which can be found here: http://www.arago.utwente.nl/comms/sotn/tentamendatabase/optics/qo/351500_Quantum_Optics_2010-11-03.pdf
They want to know [itex]g^{(2)}(\tau)=\frac{<I(t) I(t+\tau)>}{<I(t)><I(t+\tau)>}[/itex]
For [itex]\tau=0[/itex], this simplifies to [itex]\frac{<I(t)^2>}{<I(t)>^2}[/itex]
For [itex]\tau=1[/itex], it is [itex]\frac{I(t)I(t+1)>}{<I(t)><I(t+1)>}[/itex]
Now, I'd say that in the second case, the answer depends on time, since (take t=1) I(1) is not equal to I(2).
If anyone can help me out (especially understanding what exactly is going on) I'd be grateful!
Sven
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