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Second order ODE

  1. Jun 7, 2010 #1
    Ly ≡ (x +1)^2y′′− 4(x +1)y′+6y =0

    given y[1]=(x+1)^2 is a solution, use the ansatz y2(x)= u(x)(x+1)2 to reduce
    the order of the differential equation and find a second independent solution y2

    how to reduce !? and i can't find u ....can't solve (x+1)^2u''+6u=0

    please help!!
  2. jcsd
  3. Jun 7, 2010 #2


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    Welcome to PF!

    Hi samleemc! Welcome to PF! :smile:

    (try using the X2 and X2 tags just above the Reply box :wink:)

    Put y = u(x) (x+1)2 into the original equation …

    what do you get? :smile:
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